15 Algebra Word Problems for Class 6 with Answers
If you have already learned the basics of algebra for Class 6, the next step is solving algebra word problems. In this article, you will learn how to solve algebra word problems for class 6, and practice questions will also be given for your practice. After reading this article, you can easily relate the real-world problems to algebra.
How to Solve Algebra Word Problems for Class 6
Here are some key points on how to solve algebra word problems for class 6.
- Read the word problem carefully.
- Identify the unknown value.
- Let the unknown value be x.
- Write an algebraic equation.
- Solve the equation and check your answer.
Here are the 15 algebra word problems for class 6.
15 Algebra Word Problems for Class 6 with Answers
Q1. Ali is 12 years old. His sister is x years old. Together, their ages add up to 21 years. Find the age of Ali’s sister.
Solution:
According to the condition
12 + x = 21
x = 21 – 12
x = 9
So, Ali’s sister is 9 years old.
Q2. Sara has Rs 250. She spends x rupees on notebooks and has Rs 90 left. Find the amount she spent.
Solution:
According to the condition
90 + x = 250
x = 250 – 90
x = 160
Hence, she spent Rs 160 on notebooks.
Q3. A teacher has x pencils. After giving 18 pencils to students, 27 pencils remain. How many pencils did the teacher have at first?
Solution:
x – 18 =27
x = 18 + 27
x = 45
So, the teacher had 45 pencils at first.
Q4. Ahmed buys 6 chocolates. Each chocolate costs Rs 40. Write an algebraic expression for the total cost and find the total amount.
Solution:
Total Cost = 6x
Let x be the cost of each chocolate. So,
Total Cost = 6(40)
Total Cost = 240
The total cost of chocolates is Rs 240.

Q5. A library has x books. It buys 120 more books, making the total 450 books. Find the original number of books.
Solution:
x + 120 = 450
x = 450 – 120
x = 330
The original number of books is 330.
Q6. One school bag costs Rs 850. If Fatima buys x bags, write an expression for the total cost. Find the cost when x = 4.
Solution:
Total Cost = 850x
According to the problem, x = 4
Total Cost = 850(4)
Total Cost = 3400
The total cost will be Rs 3400.

Q7. The length of a rectangle is x cm, and its width is 6 cm. Write an expression for its perimeter. Find the perimeter when x = 9.
Solution:
Perimeter of a rectangle = 2(x + 6)
Given, x = 9 So,
Perimeter of a rectangle = 2(9 + 6)
Perimeter of a rectangle = 2(15)
Perimeter of a rectangle = 30 cm
Therefore, the perimeter of a rectangle is 30 cm.
Q8. A toy shop has x toy cars. It sells 15 toy cars, leaving 35. Find the original number of toy cars.
Solution:
Let the total number of cars be x.
x – 15 = 35
x = 35 + 15
x = 50
The original number of toys is 50.
Q9. A basket contains x apples. Another basket contains 18 apples. Together they contain 50 apples. Find the value of x.
Solution:
The equation will be
x + 18 = 50
x = 50 – 18
x = 32
Therefore, a basket contains 32 apples.
Q10. A school bus has x students. 12 more students get on the bus, making the total 48 students. Find the number of students at the beginning.
Solution:
According to the given problem
x + 12 = 48
x = 48 – 12
x = 36
There are 36 students in the bus at the beginning.
Q11. A rope is x metres long. After cutting 7 metres, 15 metres remain. Find the original length of the rope.
Solution:
Let x be the length of the rope. Then,
x – 7 = 15
x = 15 + 7
x = 22 m
So, the original rope’s length is 22m.
Q12. A cricket player scored x runs in the first match and 45 runs in the second match. His total score is 93 runs. Find the runs scored in the first match.
Solution:
Let x be the score of the first match.
x + 45 = 93
x = 93 – 45
x = 48
He scored 48 runs in the first match.
Q13. Each water bottle costs Rs 120. A shopkeeper sells x bottles. Write an expression for the total amount earned. Find the amount when x = 8.
Solution:
The expression will be
Total amount = 120x
Let x be the number of bottles.
Total amount = 120(8)
Total amount = 960
A shopkeeper earned Rs 960.
Q14. A box contains x notebooks. Another box contains 25 notebooks. Together they have 63 notebooks. Find the number of notebooks in the first box.
Solution:
Let x be the number of notebooks in the first box.
x + 25 = 63
x = 63 – 25
x = 38
Hence, 38 notebooks are in the first box.
Q15. A gardener planted x flowers on Monday and 35 flowers on Tuesday. Altogether, he planted 80 flowers. Find the number of flowers planted on Monday.
Solution:
Let x be the number of flowers planted on Monday.
x + 35 = 80
x = 80 – 35
x = 45
So, there are 45 flowers planted on Monday.
Practice Questions
Here are some practice question bases on how to solve algebra word problems for class 6. After the solved examples, these practice questions for class 6 will be easy to solve.
Q1. One mango costs Rs 60. If Ayesha buys x mangoes, write an algebraic expression for the total cost. Find the total cost when x = 7.
Q2. A boy walked x km in the morning and 5 km in the evening. Altogether, he walked 14 km. Find the distance walked in the morning.
Q3. There are x desks in a classroom. 10 new desks have been added, making the total 42 desks. Find the original number of desks.
Q4. Hassan has Rs x in his savings box. He deposits Rs 300, and now he has Rs 950. Find the amount he had before depositing the money.
Q5. The sum of a number and 15 is 49. Find the number.
Related Topics
You can also read about the other classes from class-wise algebra.
Here, you can get the deep information about algebra.
FAQs
Q1: How to solve algebra word problems for class 6?
The easiest way is to understand the concepts of properties and practice daily.
Q2: Why are word problems important in algebra?
It helps students to clarify concepts.
Q3: Which properties of algebra should Class 6 students know?
Commutative, Associative, Distributive, Identity, and Inverse properties.
Q4: Are algebra word problems for Class 6 difficult for beginners?
No, if students first understand the property and then solve step by step, algebra word problems for class 6 become very easy.
Conclusion
This article is about how to solve algebra word problems for class 6, shows the real method of solving problems, and includes practice questions. After this article, every beginner can easily solve word problems related to algebra.
