After reading the algebra concepts of Class 7 and problems of algebra for Class 7, you’re now able to learn about the algebra word problems for Class 7. In this section, you will solve 10 word problems related to algebra for Class 7. These examples will help you to relate real-world problems to algebra. You can easily solve the real problems in your daily life with the help of algebra.
How to Solve Algebra Word Problems for Class 7
- Read the problem carefully.
- Identify the unknown value.
- Represent the unknown with a variable (such as x).
- Write an algebraic equation.
- Solve the equation step by step.
- Verify your answer.
Algebra Word Problems for Class 7
Q1. Two integers added together equal 48. The difference between the two numbers is twelve. Find both numbers.
Solution:
Let the two numbers be x and y.
According to the condition.
x + y = 48
x – y = 12
Now x + y = 48
x = 48 – y
Now put it into eq 2
(48 – y) – y = 12
48 – y – y = 12
48 – 2y = 12
48 – 12 = 2y
36 = 2y
y = 18
x = 48 – y
x = 48 – 18
x = 30
So the two numbers are 30 and 18.
Q2. A father’s age is four times that of his son. Their ages add up to fifty years. Calculate their present ages.
Solution:
Let the son’s age be x, and then the father’s age will be 4x.
Now, x + 4x = 50
5x = 50
x = 50 / 5
x = 10
Son’s age = 10 years
Father’s age = 4(10)
= 40 years
Q3. A rectangle is 5 cm longer than it is wide. Determine the length and width given a perimeter of 50 cm.
Solution:
The length of a rectangle is 5 cm longer than its width. If the width is x, then the length will be 5+x.
Perimeter = 2 ( l + w )
50 = 2 (5 + x + x )
50 = 2(5 + 2x)
50 = 10 + 4x
50 – 10 = 4x
40 = 4x
x = 10
Width is 10cm.
Length = 5 + x
= 5 + 10 = 15 cm
Q4. Ali’s wealth is three times Sara’s. They have a total of Rs. 240. What is the amount of money each has?
Solution:
Let Sara’s wealth be x; then Ali’s wealth will be 3x.
According to the problem
x + 3x = 240
4x = 240
x = 240 / 4
x = 60
Sara has 60 rupees
Ali’s money = 3(60)
= 180 rupees
Q5. The sum of three consecutive integers is 72. Find the three numbers.
Solution:
Let the three consecutive numbers be x, x+1, and x+2.
Sum = x + x+ 1 +x + 2
3x + 3 = 72
3x = 72 – 3
3x = 69
x = 23
x + 1 = 23 + 1 = 24
x + 2 = 23 + 2 = 25
So the consecutive numbers are 23, 24, and 25.
Q6. A scientific presentation at a school sold 120 tickets. Adult tickets cost Rs. 200, while student tickets cost Rs. 100. A total of Rs. 18,000 was collected. How many tickets were sold for adults and students?
Solution:
Let
Student tickets = x
Adult tickets = y
x+y=120
100x+200y=18000
x+2y=180
Subtract the first equation
y=60
x=60
Student tickets =60
Adult tickets =60
Q7. Ayan spends Rs. 250 more on internet recharge than Hamza. Together they spend Rs. 1,150. How much does each spend?
Solution:
Let Hamza spend x rupees, and Ayan spends x+250 rupees. According to the question
x + x + 250 = 1150
2x + 250 = 1150
2x = 1150 – 250
2x = 900
x= 450
So, Hamza spends 450, and Ayan spends 700 rupees on the internet.
Q8. When 8 is added to a number, the result is three times the original number. Locate the number.
Solution:
Let the number be x.
Then,
x + 8 = 3x
8 = 3x – x
8 = 2x
x = 4
So, the number is 4.
Q9. Ahmed got six more points than Bilal on a test in class. They received a total of 74 points. Find the scores for each student.
Solution:
Let Bilal take x points, and Ahmad takes x+6 points. Their total is 74. So,
x + x + 6 = 74
2x + 6 = 74
2x = 74 – 6
2x = 68
x = 34
Bilal takes 34 points on a test, and Ahmad takes 40 points.
Q10. There are some pencils in a box. The sum is three times the initial amount after 18 pencils are added. What was the initial number of pencils in the box?
Solution:
Let there be x pencils in a box. After adding 18 pencils, they become equal to 3x.
x + 18 = 3x
18 = 3x – x
18 = 2x
x = 9
Practice Questions
Q1. The sum of two consecutive even numbers is 54. Find the numbers.
Q2. The length of a garden is 7 m more than its width. The perimeter is 54 m. Find the dimensions of the garden.
Q3. The length of a rectangle is 8 cm greater than its width. Its area is 105 cm². Find the dimensions of the rectangle.
Conclusion
In this article, you have learned the algebra word problem for class 7. After this, you will be able to solve the algebra word problems in your daily life. You can also practice them daily. After this article, the word problems won’t scare you. You can easily convert them into a mathematical equation, then solve them.
Related Topics
FAQs
Q1. What are algebra word problems for Class 7?
Algebra word problems for Class 7 are basically real-life problems that should be converted to algebraic equations to solve them.
Q2. How do you solve algebra word problems in Class 7?
Firstly, read the question carefully and identify the variable, then convert it to an equation according to the given conditions. Solve that equation and check the answer.
Q3. What types of algebra word problems are taught in Class 7?
Class 7 students commonly solve word problems based on ages, money, consecutive numbers, perimeter, area, percentages, speed, and simple linear equations.
Q4. Why are algebra word problems important for Class 7 students?
Algebra word problems help students develop problem-solving and critical thinking skills.
Q5. How can I improve at solving algebra word problems for Class 7?
By practicing the word problems daily it can improve your algebra problem-solving skills.
